Overview
- If I react 25g of x with y, I need 375g of y
Steps
Step 1: Balance
Example
- $C_4H_{10}+O_2$ → $CO_2$
- $2C_4H_{10}+13O_2$ → $8CO_2 + 10H_2O$
Step 2: Make a Plan
- Question: If I have 3.0g of butane$(C_4H_{10})$, then how many grams of $CO_2$ will be produced
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💡 $1 mol = 6.022 * 10^{23}$ atoms/particles/formula units/Molecules
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- Molar mass: number of grams in an average mol
Step 3: Calculate
Train Tracks
| $3.0g$ $C_4H_{10}$ |
$1mol$ $C_4H_{10}$ |
$8mol$ $CO_{2}$ |
$44.01g$ $CO_{2}$ |
|
$58.14g$ $C_4H_{10}$ |
$2mol$ $C_4H_{10}$ |
$1mol$ $CO_{2}$ |
$= 9.1g$ $CO_2$
